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[dstring] Ignore embedded nulls for appendstr
I don't remember why I thought it was a good idea to respect embedded nul characters, but doing so makes appendstr O(N) instead of O(1) (or O(N^2) instead of O(N) for multiple appends of n chars (N = sum(n)). Also, this makes appendstr consistent with dasprintf.
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4329537b1b
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2 changed files with 10 additions and 4 deletions
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@ -140,12 +140,12 @@ void dstring_copystr (dstring_t *dstr, const char *str);
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void dstring_copysubstr (dstring_t *dstr, const char *str, size_t len);
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/** Append the null terminated string to the end of the dstring.
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The dstring does not have to be null terminated but will become so.
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However, any embedded nulls will be treated as the end of the dstring.
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\note any embedded nulls will be ignored.
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*/
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void dstring_appendstr (dstring_t *dstr, const char *str);
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/** Append up to len bytes from the string to the end of the dstring.
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The dstring does not have to be null terminated but will become so.
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However, any embedded nulls will be treated as the end of the dstring.
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\note any embedded nulls will be ignored.
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*/
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void dstring_appendsubstr (dstring_t *dstr, const char *str, size_t len);
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/** Insert the null terminated string into the dstring at pos. The dstring
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@ -271,9 +271,12 @@ dstring_copysubstr (dstring_t *dstr, const char *str, size_t len)
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VISIBLE void
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dstring_appendstr (dstring_t *dstr, const char *str)
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{
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size_t pos = strnlen (dstr->str, dstr->size);
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size_t pos = dstr->size;
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size_t len = strlen (str);
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if (pos && !dstr->str[pos - 1]) {
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pos--;
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}
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dstr->size = pos + len + 1;
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dstring_adjust (dstr);
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strcpy (dstr->str + pos, str);
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@ -282,8 +285,11 @@ dstring_appendstr (dstring_t *dstr, const char *str)
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VISIBLE void
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dstring_appendsubstr (dstring_t *dstr, const char *str, size_t len)
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{
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size_t pos = strnlen (dstr->str, dstr->size);
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size_t pos = dstr->size;
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if (pos && !dstr->str[pos - 1]) {
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pos--;
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}
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len = strnlen (str, len);
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dstr->size = pos + len + 1;
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dstring_adjust (dstr);
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