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[qfcc] Set function attributes correctly

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The flags were being set, then promptly lost because the attribute flag
(%) wasn't in the encoding. Of course, this breaks a few things :/
This commit is contained in:
Bill Currie 2025-02-17 18:50:54 +09:00
parent 7c0f7c7bec
commit 6664503aaf
1 changed files with 17 additions and 6 deletions
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23
tools/qfcc/source/function.c
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@ -619,19 +619,31 @@ new_metafunc (void)
return metafunc;
}
static void
static const type_t *
set_func_attrs (const type_t *func_type, attribute_t *attr_list)
{
auto func = &((type_t *) func_type)->func;//FIXME
if (!is_func (func_type)) {
internal_error (0, "not a function");
}
func_type = unalias_type (func_type);
type_t new = {
.type = ev_func,
.alignment = 1,
.width = 1,
.columns = 1,
.meta = ty_basic,
.func = func_type->func,
};
for (auto attr = attr_list; attr; attr = attr->next) {
if (!strcmp (attr->name, "no_va_list")) {
func->no_va_list = true;
new.func.no_va_list = true;
} else if (!strcmp (attr->name, "void_return")) {
func->void_return = true;
new.func.void_return = true;
} else {
warning (0, "skipping unknown function attribute '%s'", attr->name);
}
}
return find_type (&new);
}
typedef struct {
@ -861,8 +873,7 @@ get_function (const char *name, specifier_t spec, rua_ctx_t *ctx)
{
spec = spec_process (spec, ctx);
spec.sym->type = spec.type;
set_func_attrs (spec.sym->type, spec.attributes);
spec.sym->type = find_type (spec.sym->type);
spec.sym->type = set_func_attrs (spec.sym->type, spec.attributes);
auto type = unalias_type (spec.sym->type);
int num_params = type->func.num_params;