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make --tradiontial cause "!foo & bar" evaluate as "!(foo & bar)" as per

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qfcc's broken behaviour.
This commit is contained in:
Bill Currie 2002-06-20 18:51:46 +00:00
parent e5c470d5e4
commit 3476138988
1 changed files with 7 additions and 2 deletions
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9
tools/qfcc/source/expr.c
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@ -1226,8 +1226,13 @@ binary_expr (int op, expr_t *e1, expr_t *e2)
if ((op == '&' || op == '|')
&& e1->type == ex_uexpr && e1->e.expr.op == '!' && !e1->paren) {
warning (e1, "ambiguous logic. Suggest explicit parentheses with "
"expressions involving ! and %c", op);
if (options.traditional) {
e1->e.expr.e1->paren = 1;
return unary_expr ('!', binary_expr (op, e1->e.expr.e1, e2));
} else {
warning (e1, "ambiguous logic. Suggest explicit parentheses with "
"expressions involving ! and %c", op);
}
}
if (t1 != t2) {