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Set up temp aliases correctly

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Fixes vector expressions as sub-expresses. I really don't know why I did
the temp alias setup that way.
This commit is contained in:
Bill Currie 2019-06-18 10:38:19 +09:00
parent fc50376297
commit 0f1f477e64
3 changed files with 23 additions and 6 deletions
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4
tools/qfcc/source/statements.c
View file

@ -889,9 +889,7 @@ expr_alias (sblock_t *sblock, expr_t *e, operand_t **op)
}
}
if (!top) {
top = new_operand (op_temp);
top->type = type;
top->size = type_size (type);
top = temp_operand (type);
top->o.tempop.alias = aop;
top->o.tempop.offset = offset;
top->next = aop->o.tempop.alias_ops;

8
tools/qfcc/test/vecexpr.r
View file

@ -21,6 +21,8 @@ int
main ()
{
int ret = 0;
float x = 4;
float y = 5;
vector v;
v = t2(5);
@ -33,5 +35,11 @@ main ()
printf("t3(5) = %v\n", v);
ret |= 1;
}
v = [x, y, 0] / 2;
if (v != [2, 2.5, 0]) {
printf("v = %v\n", v);
ret |= 1;
}
return ret;
}

17
tools/qfcc/test/vecinit.r
View file

@ -8,8 +8,8 @@ foo (float x, float y, float z)
return v;
}
float w;
float h;
float w = 2;
float h = 4;
vector
bar (void)
@ -22,8 +22,19 @@ bar (void)
return pos;
}
vector
baz (float w, float h)
{
vector p = [w, h, 0] / 2;
return p;
}
int
main ()
{
return 0;
int ret = 0;
ret |= foo(1,2,3) != [1, 2, 3];
ret |= bar() != [2, 4, 0];
ret |= baz(5, 6) != [2.5, 3, 0];
return ret;
}