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[qfcc] Avoid pointer alias of address expressions

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Since address expressions always product a pointer type, aliasing one to
another pointer type is redundant. Instead, simply return an address
expression with the desired type.
This commit is contained in:
Bill Currie 2022-02-03 14:35:43 +09:00
parent 80c6431544
commit 008359862b
1 changed files with 6 additions and 0 deletions
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6
tools/qfcc/source/expr.c
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@ -1346,6 +1346,12 @@ is_pointer_val (expr_t *e)
expr_t *
new_alias_expr (type_t *type, expr_t *expr)
{
if (is_ptr (type) && expr->type == ex_address) {
// avoid aliasing a pointer to a pointer (redundant)
expr = copy_expr (expr);
expr->e.address.type = type;
return expr;
}
if (expr->type == ex_alias) {
if (expr->e.alias.offset) {
return new_offset_alias_expr (type, expr, 0);