/* =========================================================================== Doom 3 GPL Source Code Copyright (C) 1999-2011 id Software LLC, a ZeniMax Media company. This file is part of the Doom 3 GPL Source Code ("Doom 3 Source Code"). Doom 3 Source Code is free software: you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation, either version 3 of the License, or (at your option) any later version. Doom 3 Source Code is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with Doom 3 Source Code. If not, see . In addition, the Doom 3 Source Code is also subject to certain additional terms. You should have received a copy of these additional terms immediately following the terms and conditions of the GNU General Public License which accompanied the Doom 3 Source Code. If not, please request a copy in writing from id Software at the address below. If you have questions concerning this license or the applicable additional terms, you may contact in writing id Software LLC, c/o ZeniMax Media Inc., Suite 120, Rockville, Maryland 20850 USA. =========================================================================== */ #ifndef __MATH_LCP_H__ #define __MATH_LCP_H__ #include "idlib/math/Matrix.h" #include "framework/Common.h" #include "framework/CVarSystem.h" /* =============================================================================== Box Constrained Mixed Linear Complementarity Problem solver A is a matrix of dimension n*n and x, b, lo, hi are vectors of dimension n Solve: Ax = b + t, where t is a vector of dimension n, with complementarity condition: (x[i] - lo[i]) * (x[i] - hi[i]) * t[i] = 0 such that for each 0 <= i < n one of the following holds: 1. lo[i] < x[i] < hi[i], t[i] == 0 2. x[i] == lo[i], t[i] >= 0 3. x[i] == hi[i], t[i] <= 0 Partly bounded or unbounded variables can have lo[i] and/or hi[i] set to negative/positive idMath::INFITITY respectively. If boxIndex != NULL and boxIndex[i] != -1 then lo[i] = - fabs( lo[i] * x[boxIndex[i]] ) hi[i] = fabs( hi[i] * x[boxIndex[i]] ) boxIndex[boxIndex[i]] must be -1 Before calculating any of the bounded x[i] with boxIndex[i] != -1 the solver calculates all unbounded x[i] and all x[i] with boxIndex[i] == -1. =============================================================================== */ class idLCP { public: static idLCP * AllocSquare( void ); // A must be a square matrix static idLCP * AllocSymmetric( void ); // A must be a symmetric matrix virtual ~idLCP( void ); virtual bool Solve( const idMatX &A, idVecX &x, const idVecX &b, const idVecX &lo, const idVecX &hi, const int *boxIndex = NULL ) = 0; virtual void SetMaxIterations( int max ); virtual int GetMaxIterations( void ); protected: int maxIterations; }; #endif /* !__MATH_LCP_H__ */