ast_store to take ast_expression on its left, rather than ast_value. Assigning to a vector member would not put an ast_value on the left, but an ast_member, thus: ast_expression now already

This commit is contained in:
Wolfgang Bumiller 2012-07-28 18:13:12 +02:00
parent 10d70328c8
commit c5ba27da6f
3 changed files with 4 additions and 4 deletions

2
ast.c
View file

@ -404,7 +404,7 @@ void ast_call_delete(ast_call *self)
}
ast_store* ast_store_new(lex_ctx ctx, int op,
ast_value *dest, ast_expression *source)
ast_expression *dest, ast_expression *source)
{
ast_instantiate(ast_store, ctx, ast_store_delete);
ast_expression_init((ast_expression*)self, (ast_expression_codegen*)&ast_store_codegen);

4
ast.h
View file

@ -218,11 +218,11 @@ struct ast_store_s
{
ast_expression_common expression;
int op;
ast_value *dest; /* When we add pointers this might have to change to expression */
ast_expression *dest;
ast_expression *source;
};
ast_store* ast_store_new(lex_ctx ctx, int op,
ast_value *d, ast_expression *s);
ast_expression *d, ast_expression *s);
void ast_store_delete(ast_store*);
bool ast_store_codegen(ast_store*, ast_function*, bool lvalue, ir_value**);

View file

@ -42,7 +42,7 @@ do { \
} while(0)
#define ASSIGN(op, a, b) \
(ast_expression*)ast_store_new(ctx, INSTR_##op, (a), (ast_expression*)(b))
(ast_expression*)ast_store_new(ctx, INSTR_##op, (ast_expression*)(a), (ast_expression*)(b))
#define BIN(op, a, b) \
(ast_expression*)ast_binary_new(ctx, INSTR_##op, (ast_expression*)(a), (ast_expression*)(b))